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Bratkova, Anna (1201) - Buchloh, Adrian (1639) - Pardubice Czech op-D 29th (1), Pardubice, 2018
B01

1.e4 d5 2.exd5 Qxd5 3.Nc3 Qa5 4.d4 Nf6 5.Nf3 Bg4 6.Bc4 Nc6 7.Bd2 O-O-O 8.Nd5 Qa4 9.b3 Qa3 10.Bc1 Qd6 11.Bf4 e5 12.dxe5 Nxe5 13.Bxe5 Re8 14.Qe2 Bxf3 15.Bxd6 Bxe2 16.Bxe2 Nxd5 17.Bxf8 Rhxf8 18.Kf1 Nc3 19.Bd3 Rd8 20.g3 Rfe8 21.Kg2 g6 22.a4 f5 23.h4 Nd5 24.Bc4 Nb4 25.c3 Nd5 26.Rac1 Nf6 27.Rhe1 Rxe1 28.Rxe1 Ne4 29.Re3 Rd2 30.Rf3 Kd8 31.Bg8 Nf6 32.Be6 Ke7 33.Bc8 b6 34.Bb7 c5 35.c4 Kd7 36.Re3 Ng4 37.Rf3 Ke7 38.Bd5 Kf6 39.Bg8 Kg7 40.Bd5 h6 41.Kg1 Kf6 42.Bg8 Ne5 43.Re3 Rd3 44.Bd5 Rxe3 45.fxe3 Ng4 46.Bf3 Nxe3 47.Kf2 Nc2 48.Bd1 Nd4 49.Kf1 Ke5 50.Ke1 Ke4 51.Kd2 g5 52.hxg5 hxg5 53.Kc3 f4 54.gxf4 gxf4 55.b4 a5 56.bxc5 bxc5 57.Bg4 Ke3 58.Bd1 f3 59.Bxf3 Nxf3 60.Kc2 Kd4 61.Kb3 Nd2+ 62.Kc2 Kxc4 63.Kxd2 Kb4 64.Kd3 Kb3 65.Kd2 c4 66.Kc1 Kc3 67.Kb1 Kd2 68.Kb2 c3+ 69.Kb1 c2+ 70.Ka2 c1=Q 71.Kb3 Qc3+ 72.Ka2 Qb4 73.Ka1 Kc2 74.Ka2 Qxa4# 0-1

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