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Bykova, Anastasia
(2229) -
Sarkar, Justin
(2389) -
Pardubice Czech op-A 30th
(8), Pardubice, 2019
E10
1.d4
Nf6
2.c4
e6
3.Nf3
c5
4.d5
b5
5.e4
Nxe4
6.Bd3
Nf6
7.O-O
bxc4
8.Bxc4
Ba6
9.Bxa6
Nxa6
10.Nc3
Qc8
11.Re1
Be7
12.d6
Bd8
13.Ne5
Nb4
14.a3
Nc6
15.f4
Nd4
16.Be3
Rb8
17.Rc1
Nb3
18.Rc2
Ba5
19.Rf1
O-O
20.g4
Qb7
21.Rg2
Bxc3
22.bxc3
Nd5
23.Bd2
f6
24.Nf3
Qa6
25.f5
c4
26.fxe6
dxe6
27.Be1
Qxd6
28.Kh1
Qxa3
29.Bg3
Ne3
30.Qe2
Nxf1
31.Qxe6+
Kh8
32.Bxb8
Rxb8
33.g5
Qc1
34.h3
Qf4
35.gxf6
Qxf6
36.Qe4
Rf8
37.Ng5
Qf5
38.Qe7
h6
39.Ne6
Qxh3+
40.Kg1
Qe3+
41.Kh1
Qh3+
42.Kg1
Qe3+
43.Kh1
Ng3+
44.Kh2
Rg8
45.Rxg3
Qe5
46.Qf7
Nd2
47.Nf4
Qf6
48.Qxf6
gxf6
49.Rh3
Rg4
50.Nd5
Kg7
51.Kh1
f5
52.Ne3
Rg5
53.Nd5
Ne4
54.Rh2
Kf7
55.Ra2
Ke6
56.Ra5
Kd6
57.Ne3
f4
58.Nxc4+
Kc6
59.Rxa7
Rc5
60.Nb2
Rxc3
61.Ra6+
Kd5
62.Rxh6
f3
63.Rh5+
Kd4
64.Nd1
Rc1
65.Kh2
Rxd1
66.Rf5
Rh1+
67.Kxh1
Ng3+
0-1
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