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Bowcott Terry, Finlay (1695) - Chan, Sheng Liang Bernard (1745) - London Classic U1825 op 10th (4), London, 2018
B01

1.e4 d5 2.exd5 Qxd5 3.Nc3 Qd8 4.Nf3 Bg4 5.Be2 Nf6 6.h3 Bh5 7.d4 e6 8.O-O c6 9.Bf4 Bxf3 10.Bxf3 Bd6 11.Qd2 O-O 12.Rad1 Qc7 13.Bxd6 Qxd6 14.Ne4 Nxe4 15.Bxe4 Nd7 16.c3 Rad8 17.Qe2 Nf6 18.Bb1 g6 19.Rfe1 Rd7 20.Qf3 Kg7 21.Qg3 Qxg3 22.fxg3 Rfd8 23.Bc2 h5 24.Kf2 c5 25.dxc5 Rxd1 26.Rxd1 Rxd1 27.Bxd1 Ne4+ 28.Ke3 Nxc5 29.Kd4 b6 30.Bf3 Kf6 31.Kc4 Ke7 32.Kb5 Kd6 33.b4 Nd7 34.Ka6 f5 35.Kxa7 e5 36.Kb7 e4 37.Be2 Nf6 38.c4 Nd7 39.a4 e3 40.Bf1 g5 41.Be2 h4 42.gxh4 gxh4 43.Bf1 f4 44.Be2 Ke7 45.Kc7 Ke6 46.Kc6 f3 47.gxf3 Ne5+ 48.Kxb6 Kf5 49.a5 Kf4 50.a6 Kg3 51.a7 Kf2 52.a8=Q Kxe2 53.Qa2+ Kxf3 54.Qa1 Nxc4+ 55.Kc5 Nd2 56.Qd1+ Kf2 57.b5 Nf3 58.b6 e2 59.Qxe2+ Kxe2 60.b7 Ne5 61.Kd6 Nf7+ 62.Kc7 Ng5 63.b8=Q Kf2 64.Qb4 Nf3 65.Qg4 Ke3 66.Kd6 Nd4 67.Ke5 Nf3+ 68.Kd5 Ne1 69.Qxh4 Ng2 70.Qe4+ 1-0

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