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Burman, Ray Pritish (1825) - Lundberg, B (2173) - Hong Kong Open 2025 (2.26), Hong Kong HKG, 2025
E11

1.d4 Nf6 2.c4 e6 3.Nf3 Bb4+ 4.Nbd2 d5 5.Qa4+ Nc6 6.e3 a5 7.Bd3 dxc4 8.Bxc4 O-O 9.O-O Bd7 10.Qc2 a4 11.a3 Be7 12.b4 axb3 13.Nxb3 Na5 14.Nxa5 Rxa5 15.Bd2 Ra4 16.Ne5 Be8 17.Qb3 c5 18.Qxb7 cxd4 19.Bb5 Qa8 20.Qxa8 Rxa8 21.Bxe8 Rfxe8 22.a4 Ne4 23.Bc1 Nc3 24.a5 Bc5 25.Nd3 Bb6 26.exd4 Rxa5 27.Rxa5 Bxa5 28.Nf4 Rd8 29.Bd2 Rxd4 30.Be3 Rxf4 31.Bxf4 Ne2+ 32.Kh1 Nxf4 33.Ra1 Bb4 34.g3 Nd5 35.Ra8+ Bf8 36.f4 f5 37.Kg2 Kf7 38.Kf3 h6 39.h3 Bd6 40.Ra6 Bc7 41.Ra7 Kf6 42.h4 g5 43.hxg5+ hxg5 44.fxg5+ Kxg5 45.Ra8 e5 46.Rg8+ Kf6 47.Rf8+ Kg6 48.Rg8+ Kf7 49.Rg5 e4+ 50.Kf2 Kf6 51.Rg8 Ke5 52.Re8+ Kd4 53.Rf8 Ne7 54.Rf7 Bd6 55.Rf6 Ke5 56.Rf7 Nd5 57.Ke2 Nf6 58.Ra7 Ke6 59.Ra6 Nh5 60.g4 fxg4 61.Ra5 Be5 62.Ke3 Kf5 63.Ra8 Nf6 64.Rf8 g3 65.Rf7 Bd6 66.Rg7 Ng4+ 67.Ke2 g2 68.Rf7+ Ke6 69.Rf2 g1=Q 70.Rf4 Qe3+ 71.Kf1 Qxf4+ 0-1

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